(y+3)(2y^2+4y-3)=

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Solution for (y+3)(2y^2+4y-3)= equation:


Simplifying
(y + 3)(2y2 + 4y + -3) = 0

Reorder the terms:
(3 + y)(2y2 + 4y + -3) = 0

Reorder the terms:
(3 + y)(-3 + 4y + 2y2) = 0

Multiply (3 + y) * (-3 + 4y + 2y2)
(3(-3 + 4y + 2y2) + y(-3 + 4y + 2y2)) = 0
((-3 * 3 + 4y * 3 + 2y2 * 3) + y(-3 + 4y + 2y2)) = 0
((-9 + 12y + 6y2) + y(-3 + 4y + 2y2)) = 0
(-9 + 12y + 6y2 + (-3 * y + 4y * y + 2y2 * y)) = 0
(-9 + 12y + 6y2 + (-3y + 4y2 + 2y3)) = 0

Reorder the terms:
(-9 + 12y + -3y + 6y2 + 4y2 + 2y3) = 0

Combine like terms: 12y + -3y = 9y
(-9 + 9y + 6y2 + 4y2 + 2y3) = 0

Combine like terms: 6y2 + 4y2 = 10y2
(-9 + 9y + 10y2 + 2y3) = 0

Solving
-9 + 9y + 10y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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